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71. Program a structure which stores information about hotels which stores information about name, grade, room change, no of rooms.
a) a) Print the hotels of given grade in order of roomchange.
b) b) Print the hotels with roomchange less than a given change.
#include<stdio.h>
#include<conio.h>
main( )
{
struct hotel
{
char name[20];
char city[10];
char grade;
int rc,nr;
};
struct hotel ht[20],t;
int i,n,j,c;
char gr;
clrscr( );
printf(“enter no. of hotels\n”);
scanf(“%d”,&n);
for(i=0;i<n;i++)
{
printf(“enter name of hotel \n”);
scanf(“%s”,&ht[i].name);
printf(“enter name of city \n”);
scanf(“%s”,&ht[i].city);
printf(“enter the grade \n”);
scanf(“%s”.ht[i].grade);
ht[i].grade=getche( );
printf(“enter room charge \n”);
scanf(“%d”,&ht[i].rc);
printf(“enter no of rooms \n”);
scanf(“%d”,&ht[i].nr);
}
for(i=0;i<n;i++)
for(j=0;j<n-i;j++)
{
t=ht[j];
ht[j]=ht[j+i];
ht[j+1]=t;
}
printf(“enter a grade to print the hotels \n”);
gr=getche();
clrscr();
printf(“hotel name city grade roomcharge no of room”);
for(i=0;i<n;i++)
if(gr==ht[i].grade)
printf(“%s %s %c %d %d”,ht[i].name,ht[i].city,ht[i].grade,ht[i].rc,ht[i].nr);
getch();
printf(“enter a room charge to print hotels less than given charge \n”);
scanf(“%d”,&c);
printf(“hotel name city grade roomcharge no of rooms”);
for(i=0;i<n;i++)
if(c<=ht[i].rc)
printf(“%s %s %c %d %d”,ht[i].name,ht[i].city,h[i].grade,ht[i].rc,ht[i].nr);
}
72. Program which does the below process after reading on odd no of integer.
a) a) Print them in given order.
b) b) Replace second elements by product of first and last element
c) c) Replace middle value by average of all elements.
d) d) Replace all –ve no’s by zero’s.
#include<stdio.h>
#include<conio.h>
main( )
{
int a[10],i,n,sum=0;
clrscr( );
printf(“enter the array sixe “);
scanf(“%d”,&n);
printf(“enter the elements”);
for(i=0;i<n;i++)
{
scanf(“%d”,&a[i]);
sum=sum+a[i];
}
printf(“The given arrays is: “);
for(i=0;i<n;i++)
printf(“%d”,a[i]);
a[2]=a[1]*a[n-1];
printf(“\n the given areay after replacing 2nd element is”);
for(i=0;i<n;i++)
printf(“%d”,a[i]);
a[(1+n/2)]=sum/n;
printf(“\n the given array after replacing middle element by average of all”);
for(i=0;i<n;i++)
if(a[i]<0)
a[i]=0;
printf(“\n given array after replacing –ve values by zero”);
for(i=0;i<n;i++)
printf(“%d”,a[i]);
printf(“\n”);
getch();
}
73. Program to sort the entered elements using selection sort technique.
#include<stdio.h>
#include<conio.h>
main( )
{
int a[100],i,n,j,t,min,pos;
clrscr();
printf(“enter the array size”);
scanf(“%d”,&n);
printf(“enter the elements”);
for(i=0;i<n;i++)
scanf(“%d”,&a[i]);
for(i=0;i<n;i++)
{
min=a[i];
pos=i;
for(j=0;j<n-1;j++)
if(min>a[j])
{
min=j;
pos=j;
}
t=a[i];
a[i]=a[pos];
a[pos]=t;
}
printf(“the sorted elements are”);
for(i=0;i<n;i++)
printf(“%2d”,a[i]);
getch( );
}
74. Program to find whether a number is divisible by ‘11’ or not without actual division.
#include<stdio.h>
#include<conio.h>
#include<math.h>
main( )
{
int a,b,n,evensum=0,oddsum=0,div;
clrscr( );
printf(“enter a number”);
scanf(“%d”,&n);
a=n;
b=n/10;
while(a>0)
{
oddsum=oddsum+(a%10);
a=a/10;
}
while(b>0)
{
evensum=evensum+(b%10);
b=b/10;
}
div=abs(evensum-oddsum);
if(div%11==0)
printf(“The number is divisible by 11”);
else
printf(“The number is not divisible by 11”);
getch();
}
75. Program to find maximum and minimum of entered ’n’ number using arrays.
#include<stdio.h>
#include<conio.h>
main( )
{
int i,n,a[10],min,max;
clrscr( );
printf(“ enter how many number”);
scanf(“%d”,&n);
printf(“enter the elements”);
for(i=0;i<n;i++)
scanf(”%d”,&a[i]);
min=a[0];
for(i=0;i<n;i++)
if(min>a[i])
min=a[i];
printf(“minimum=%d”,min);
max=0;
for(i=0;i<n;i++)
if(max<a[i]);
max=a[i];
printf(“\n maximum=%d”,max);
getch( );
}
76. Program to print the following series until there sum exceeds 2.6 term value exceeds 1.5
x+x2/2!+x3/3!+------------.
#include<stdio.h>
#include<conio.h>
main( )
{
float x,sum=0,prod=1;
int i;
clrscr( );
printf(“enter x value”);
scanf(“%f’,&x);
i=1;
while((sum<2.6)&&(prod<=1.5))
{
prod=prod*(x/i);
if(prod<=1.5)
sum=sum+prod;
if(sum>2.6)
{
sum=sum-prod;
break;
}
printf(“sum=;%f’,sum);
i++;
}
getch( );
}
77. Program to print a frequency distribution table for a class of 20-students in the following format.
The marks range form 1-25.
class intertval frequency
1-5 1-5 -
6-10 6-10 -
11-15 11-15 -
16-20 16-20 -
21-25 21-25 -
#include<stdio.h>
#include<conio.h>
main( )
{
int a[20],i,n1=0,n2=0,n3=0,n4=0,n5=0;
clrscr();
printf(“enter the any 20 no of range(1-25));
for(i=1;i<=20;i++)
scanf(“%d”,&a[i]);
for(i=1;i<=20;i++)
if((a[i]>=1)&&(a[i]<6))
n1++;
else
if((a[i]>5)&&(a[i]<11))
n2++;
else
if((a[i]>10)&&(a[i]<16))
n3++;
else
if((a[i]>15)&&(a[i]<21))
n4++;
else
if((a[i]>20)&&(a[i]<26))
n5++;
printf(“class interval frequency”);
printf(“\n 1-5 %d”,n1);
printf(“\n 6-10 %d”,n2);
printf(“\n 11-15 %d”,n3);
printf(“\n 16-20 %d”,n4);
printf(“\n 21-25 %d”,n5);
getch();
}
78. Program to accept values into an array and print array in reverse and original format by using three different functions.
#include<stdio.h>
#include<conio.h>
void read_array(int x[]);
void print_array(int y[]);
void rev_array(int z[]);
main()
{
int a[5];
clrscr();
read_array(a);
printf_array(a);
rev_array(a);
getch( );
}
void read_array(int x[])
{
int i;
for(i=0;i<=4;i++)
{
printf(“enter values for a[%d]:”,i);
scanf(“%d”,&x[i]);
}
}
void print_array(int y[])
{
int i;
for(i=0;i<=4;i++)
printf(“%d”,y[i]);
}
void rev_array(int z[])
{
int i;
for(i=4;i>=0;i--)
printf(“\n%d”,z[i]);
}
79. Program to accept values into single dimensional array and print the array in reverse by using pointers.
#include<stdio.h>
#include<conio.h>
main( )
{
int a[5],*b,i;
clrscr( );
b=&a[0];
for(i=0;i<=4;i++)
{
printf(“enter a value for a[%d];”.i);
scanf(“%d”,b);
b++;
}
b=&a[4];
for(i=0;i<=4;i++)
{
printf(“\n%d”,*b);
b-- ;
}
getch( );
}
80. Program to read a string and print the number of characters in each word of the string.
#include<stdio.h>
#include<conio.h>
#include<string.h>
main( )
{
char s[100];
int i,l,nc=0;
clrscr( );
printf(“enter the sting”);
gets(s);
l=strlen(s);
for(i=0;i<l;i++)
{
if(s[i]!=’ ‘)
{
nc=0;
while(s[i]!=’ ‘)
{
printf(“%c”,s[i]);
i++;
if(s[i]=’\0’)
break;
}
printf(“\t\t %d”,nc);
printf(“\n”);
}
}
getch();
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